17 NovModeling the Math

I used Excel to enter the power calculations on a simulated data set (voltage and current). I later wanted something more responsive to what-ifs and designed for mathematical computation. I stumbled on a MatLab like open source tool cal GNU-Octave. I decided to download and install the tool to enter basic power calculations.

What I like about this tool and like Matlab is the ability to manipulate matrices and vectors. I can set up calculations for my power without resorting to annoying for loops. With my short attention span, I liked this.

Earlier I described the basic math and reduced the following salient equations:

P_{avg}=\frac {1}{T}\int^{to+T}_{to}p(t)dt\qquad(1)

I_{equiv}=I_{rms}=\sqrt{\frac {1}{T}\int^{to+T}_{to}i^2(t)dt} \qquad(2)

P_{avg} = V_{rms}I_{rms}cos(\Theta_v-\Theta_i) \qquad(3))

For giggles, I wanted to use Octave to calculate and plot power curves. I know from sampling theory that we need to sample at least at the Nyquist frequency to be able to reconstruct the signal.The reality is we don’t live in an ideal world with perfect filters. More about sampling rate later.

I created functions in Octave to generate a waveform. I can also import a text file with data values and compute the various types of powers as well. I wanted to test a couple of sunny day scenarios to ensure that my calculations were correct. I took two approaches. One I actually defined the function and let Octave integrate it. The other was to sample the function like I would in the software. Both yielded the same results. The table below outlines the expected and actual results.

Test #DescriptionMeasurement PointExpectedActualComment
160 Hz Phase 0, Vm=Im=1VrmsVm*sqrt(2)=0.7070.707pass
160 Hz Phase 0, Vm=Im=1IrmsIm*sqrt(2)=0.7070.707pass
160 Hz Phase 0, Vm=Im=1Apparent Power Vrms*Irms = 0.50.5pass
160 Hz Phase 0, Vm=Im=1Average Power Apparent Power * cos( 0-0)=.50.5pass
160 Hz Phase 0, Vm=Im=1Reactive Powerapparent power * sin (0-0) = 0.00.0pass
160 Hz Phase 0, Vm=Im=1Power Factor cos(0-45)=11.0pass
260 Hz Phase I=45 degrees, Vm=Im=1VrmsVm*sqrt(2)=0.7070.707pass
260 Hz Phase I=45 degrees, Vm=Im=1IrmsIm*sqrt(2)=0.7070.707pass
260 Hz Phase I=45 degrees, Vm=Im=1Apparent PowerVrms*Irms = 0.50.5pass
260 Hz Phase I=45 degrees, Vm=Im=1Average PowerApparent Power * cos( 0-45)=0.353550.35355pass
260 Hz Phase I=45 degrees, Vm=Im=1Reactive PowerApparent Power * sin( 0-45)=0.353550.35355pass
260 Hz Phase I=45 degrees, Vm=Im=1Power Factor cos( 0 - 45 ) = 0.707 0.707pass

I also generated an odd current waveform that could occur in speed control via a triac or something and ploted the graph below.

SCR

Intuitively one would expect the average power to be half of the sunny day scenario. The other half is reactive power. The following shows the power calculations for varying sampling rates.

Sampling RatePower Calcs
10,000 samples per secondVrms = 0.70711
Irms = 0.49990
apparentpwr = 0.35348
avaragepwr = 0.24990
reactivePower = 0.25000
pf = 0.70697
pfAngle = 45.011
1000 samples per secondVrms = 0.70711
Irms = 0.49900
apparentpwr = 0.35285
avaragepwr = 0.24900
reactivePower = 0.25000
pf = 0.70569
pfAngle = 45.115
600 samples per secondVrms = 0.70711
Irms = 0.49833
apparentpwr = 0.35237
avaragepwr = 0.24833
reactivePower = 0.24999
pf = 0.70475
pfAngle = 45.191
120 samples per secondVrms = 0.70711
Irms = 0.49160
apparentpwr = 0.34761
avaragepwr = 0.24167
reactivePower = 0.24986
pf = 0.69522
pfAngle = 45.955